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Communication with Contextual Uncertainty

机译:与语境不确定性的沟通

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摘要

We introduce a simple model illustrating the role of context in communicationand the challenge posed by uncertainty of knowledge of context. We consider avariant of distributional communication complexity where Alice gets someinformation $x$ and Bob gets $y$, where $(x,y)$ is drawn from a knowndistribution, and Bob wishes to compute some function $g(x,y)$ (with highprobability over $(x,y)$). In our variant, Alice does not know $g$, but onlyknows some function $f$ which is an approximation of $g$. Thus, the functionbeing computed forms the context for the communication, and knowing itimperfectly models (mild) uncertainty in this context. A naive solution would be for Alice and Bob to first agree on some commonfunction $h$ that is close to both $f$ and $g$ and then use a protocol for $h$to compute $h(x,y)$. We show that any such agreement leads to a large overheadin communication ruling out such a universal solution. In contrast, we show that if $g$ has a one-way communication protocol withcomplexity $k$ in the standard setting, then it has a communication protocolwith complexity $O(k \cdot (1+I))$ in the uncertain setting, where $I$ denotesthe mutual information between $x$ and $y$. In the particular case where theinput distribution is a product distribution, the protocol in the uncertainsetting only incurs a constant factor blow-up in communication and error. Furthermore, we show that the dependence on the mutual information $I$ isrequired. Namely, we construct a class of functions along with a non-productdistribution over $(x,y)$ for which the communication complexity is a singlebit in the standard setting but at least $\Omega(\sqrt{n})$ bits in theuncertain setting.
机译:我们引入一个简单的模型来说明上下文在交流中的作用以及上下文知识不确定性带来的挑战。我们考虑了分布通信复杂度的各种变量,其中Alice得到一些信息$ x $,Bob得到$ y $,其中$(x,y)$是从已知分布中得出的,而Bob希望计算某些函数$ g(x,y)$ (具有超过(x,y)$的高概率)。在我们的变体中,爱丽丝不知道$ g $,但是只知道某些函数$ f $,它是$ g $的近似值。因此,所计算的功能形成了通信的上下文,并在此上下文中不完全了解(轻度)不确定性。天真的解决方案是让Alice和Bob首先就一些接近$ f $和$ g $的通用函数$ h $达成一致,然后使用$ h $的协议来计算$ h(x,y)$。我们表明,任何此类协议都会导致大量通信开销,从而排除了这种通用解决方案。相反,我们表明,如果$ g $在标准设置中具有复杂性$ k $的单向通信协议,则在不确定情况下它具有复杂性$ O(k \ cdot(1 + I))$的通信协议,其中$ I $表示$ x $和$ y $之间的相互信息。在输入分配是产品分配的特定情况下,不确定设置中的协议只会引起通信和错误中的常数爆破。此外,我们表明需要依赖于互信息$ I $。即,我们构造一类函数以及$(x,y)$上的非乘积分布,其通信复杂度在标准设置下为一位,但在其中至少包含$ \ Omega(\ sqrt {n})$位不确定的设置。

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